amount sum col

@@ -417,13 +417,14 @@ class BSWorkbook(Workbook):
             for i in range(max_column - src_header_len):
                 header.append(None)
 
-        add_col = ['核对结果']
+        add_col = ['核对结果', '合计']
         if amount_cell_idx is None:
             if income_cell_idx is not None or outlay_cell_idx is not None:
-                add_col = ['金额', '核对结果']
+                add_col = ['金额', '核对结果', '合计']
                 amount_cell_idx = len(header)
         header.extend(add_col)
-        result_idx = len(header) - 1
+        result_idx = len(header) - 2
+        amount_sum_idx = len(header) - 1
 
         tmp_ws = self.create_sheet('tmp_ws')
         tmp2_ws = self.create_sheet('tmp2_ws')
@@ -478,7 +479,9 @@ class BSWorkbook(Workbook):
                     fill_row.add(summary_cell.row)
 
                 # 户名高亮
+                row_num = 2
                 for cell in rows:
+                    row_num = cell.row
                     if cell.value == role_name:
                         fill_row.add(summary_cell.row)
                         break
@@ -529,8 +532,8 @@ class BSWorkbook(Workbook):
                                     amount_cell.value, set()).add(amount_cell.row)
 
                 # 3.5.核对结果
+                amount_col_letter = get_column_letter(amount_cell_idx + 1)
                 if amount_success and over_success and amount_cell.row > 2:
-                    amount_col_letter = get_column_letter(amount_cell_idx + 1)
                     over_col_letter = get_column_letter(over_cell_idx + 1)
                     if is_reverse:
                         rows[result_idx].value = '=IF({2}{0}=ROUND(SUM({2}{1},{3}{0}),4), "{4}", "{5}")'.format(
@@ -539,6 +542,11 @@ class BSWorkbook(Workbook):
                         rows[result_idx].value = '=IF({2}{0}=ROUND(SUM({2}{1},{3}{0}),4), "{4}", "{5}")'.format(
                             amount_cell.row, amount_cell.row - 1, over_col_letter, amount_col_letter, *self.proof_res)
 
+                # 3.6 金额合计列
+                amount_sum_letter = get_column_letter(amount_sum_idx + 1)
+                rows[amount_sum_idx].value = '=SUM({0}{1},{2}{3})'.format(
+                    amount_sum_letter, row_num - 1, amount_col_letter, row_num)
+
                 # 3.2.提取信息、高亮
                 # row = summary_cell.row
                 if summary_cell is not None: